3[(2p+1)-(p+1)]=18

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Solution for 3[(2p+1)-(p+1)]=18 equation:


Simplifying
3[(2p + 1) + -1(p + 1)] = 18

Reorder the terms:
3[(1 + 2p) + -1(p + 1)] = 18

Remove parenthesis around (1 + 2p)
3[1 + 2p + -1(p + 1)] = 18

Reorder the terms:
3[1 + 2p + -1(1 + p)] = 18
3[1 + 2p + (1 * -1 + p * -1)] = 18
3[1 + 2p + (-1 + -1p)] = 18

Reorder the terms:
3[1 + -1 + 2p + -1p] = 18

Combine like terms: 1 + -1 = 0
3[0 + 2p + -1p] = 18
3[2p + -1p] = 18

Combine like terms: 2p + -1p = 1p
3[1p] = 18

Remove brackets around [1p]
3 * 1p = 18

Multiply 3 * 1
3p = 18

Solving
3p = 18

Solving for variable 'p'.

Move all terms containing p to the left, all other terms to the right.

Divide each side by '3'.
p = 6

Simplifying
p = 6

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